Which of the following cannot be checked in a switch-case statement?

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Which of the following cannot be checked in a switch-case statement?



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1) What will be the output of the following C code? (Assuming that we have entered the value 1 in the standard input)

 #include <stdio.h>
void main()
{
int ch;
printf("enter a value between 1 to 2:");
scanf("%d", &ch);
switch (ch, ch + 1)
{
case 1: printf("1\n");
break;
case 2: printf("2");
break;
}
}

2) Switch statement accepts.

3) What is the output of this C code(When 2 is entered)?

#include <stdio.h>
void main()
{
int ch;
printf("enter a value btw 1 to 2:");
scanf("%d", &ch);
switch (ch)
{
case 1: printf("1\n");
break;
printf("hi");
default: printf("2\n");
}
}

4) What is the output of this C code?

#include <stdio.h>
int main()
{
switch (printf("Do"))
{
case 1: printf("First\n");
break;
case 2: printf("Second\n");
break;
default: printf("Default\n");
break;
}
}

5) What will be the output of the following C code? (Assuming that we have entered the value 2 in the standard input)

 #include <stdio.h>
void main()
{
int ch;
printf("enter a value between 1 to 2:");
scanf("%d", &ch);
switch (ch)
{
case 1: printf("1\n");
break;
printf("Hi");
default: printf("2\n");
}
}

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