Which of the following cannot be checked in a switch-case statement?

Which of the following cannot be checked in a switch-case statement?

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1) What will be the output of the following C code? (Assuming that we have entered the value 1 in the standard input)

 #include <stdio.h>
 void main()
 {
    int ch;
    printf("enter a value between 1 to 2:");
    scanf("%d", &ch);
    switch (ch, ch + 1)
    {
      case 1: printf("1\n");
              break;
      case 2: printf("2");
              break;
    }
 }

2) Switch statement accepts.

3) What is the output of this C code(When 2 is entered)?

#include <stdio.h>
     void main()
     {
         int ch;
         printf("enter a value btw 1 to 2:");
         scanf("%d", &ch);
         switch (ch)
         {
         case 1:             printf("1\n");
             break;
             printf("hi");
         default:             printf("2\n");
         }
     }

4) What is the output of this C code?

#include <stdio.h>
     int main()
     {
         switch (printf("Do"))
         {
         case 1:             printf("First\n");
             break;
         case 2:             printf("Second\n");
             break;
         default:             printf("Default\n");
             break;
         }
     }

5) What will be the output of the following C code? (Assuming that we have entered the value 2 in the standard input)

 #include <stdio.h>
 void main()
 {
   int ch;
   printf("enter a value between 1 to 2:");
   scanf("%d", &ch);
   switch (ch)
   {
     case 1: printf("1\n");
             break;
             printf("Hi");
     default: printf("2\n");
   }
 }