Which of the following cannot be checked in a switch-case statement?

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Which of the following cannot be checked in a switch-case statement?



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1) What will be the output of the following C code? (Assuming that we have entered the value 1 in the standard input)

 #include <stdio.h>
void main()
{
char *ch;
printf("enter a value between 1 to 3:");
scanf("%s", ch);
switch (ch)
{
case "1": printf("1");
break;
case "2": printf("2");
break;
}
}

2) What will be the output of the following C code? (Assuming that we have entered the value 1 in the standard input)

 #include <stdio.h>
void main()
{
int ch;
printf("enter a value between 1 to 2:");
scanf("%d", &ch);
switch (ch, ch + 1)
{
case 1: printf("1\n");
break;
case 2: printf("2");
break;
}
}

3) What is the output of this C code?

#include <stdio.h>
const int a = 1, b = 2;
int main()
{
int x = 1;
switch (x)
{
case a: printf("yes ");
case b: printf("no\n");
break;
}
}

4) Consider the following code snippet:

 marks =80;
switch (marks)
{
case 60: grade = 'C';
break;
case 70: grade = 'B';
break;
case 80: grade = 'A';
break;
default: grade = 'E';
}
What is the value of 'grade' after the switch statement is executed?

5) What is the output of this C code(When 1 is entered)?

#include <stdio.h>
void main()
{
int ch;
printf("enter a value btw 1 to 2:");
scanf("%d", &ch);
switch (ch, ch + 1)
{
case 1: printf("1\n");
break;
case 2: printf("2");
break;
}
}

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