In C, if you pass an array as an argument to a function, what actually gets pass

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In C, if you pass an array as an argument to a function, what actually gets passed?



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1) In C, if you pass an array as an argument to a function, what actually gets passed?

2) What will be the output of the program if the array begins at 65472 and each integer occupies 2 bytes?

#include <stdio.h>
void main()
{
int a[3][4] = {1, 2, 3, 4, 4, 3, 2, 1, 7, 8, 9, 0};
printf("%u, %u", a+1, &a+1);
}

3) What will be the output of the program ?

 #include<stdio.h>
int main()
{
int a[5] = {51, 1, 5, 20, 25};
int x, y, z;
x = ++a[1];
y = a[1]++;
z = a[x++];
printf("%d, %d, %d", x, y, z);
return 0;
}

4) What will be printed after execution of the following code?

void main()
{
int arr[10] = {1,2,3,4,5};
printf("%d", arr[5]);
}

5) What will be printed after execution of the following code?

void main()
{
int arr[10] = {1,2,3,4,5};
printf("%d", arr[5]);
}

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