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What will be the output of the program in 16 bit platform (Turbo C under DOS)?

#include<stdio.h>
int main()
 {
     int fun();
     int i;
     i = fun();
     printf("%d\n", i);
     return 0;
 }
 int fun()
 {
     _AX = 1990;
 }

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1) What will be the output of the program?

#include<stdio.h>
int func1(int);
int main()
 {
     int k=35;
     k = func1(k=func1(k=func1(k)));
     printf("k=%d\n", k);
     return 0;
 }
 int func1(int k)
 {
     k++;
     return k;
 }

2) What will be the output of the program?

#include<stdio.h>
int reverse(int);
int main()
{
     int no=5;
     reverse(no);
     return 0;
 }
int reverse(int no)
 {
     if(no == 0)
         return 0;
     else
         printf("%d,", no);
     reverse (no--);
 }

3) What will be the output of the program?

#include<stdio.h>
int i;
int fun();
int main()
 {
     while(i)
     {
         fun();
         main();
     }
     printf("Hello\n");
     return 0;
 }
 int fun()
 {
     printf("Hi");
 }

4) What will be the output of the program?

#include<stdio.h>
void fun(int);
typedef int (*pf) (int, int);
int proc(pf, int, int);
int main()
 {
     int a=3;
     fun(a);
     return 0;
 }
void fun(int n)
 {
     if(n > 0)
     {
         fun(--n);
         printf("%d,", n);
         fun(--n);
     }
 }

5) What will be the output of the program?

#include<stdio.h>
void fun(int*, int*);
int main()
 {
     int i=5, j=2;
     fun(&i, &j);
     printf("%d, %d", i, j);
     return 0;
 }
 void fun(int *i, int *j)
 {
     *i = *i**i;
     *j = *j**j;
 }