If int is 2 bytes wide.What will be the output of the program?
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If int is 2 bytes wide.What will be the output of the program?

#include <stdio.h>
void fun(char**);
int main()
{
char *argv[] = {"ab", "cd", "ef", "gh"};
fun(argv);
return 0;
}
void fun(char **p)
{
char *t;
t = (p+= sizeof(int))[-1];
printf("%s\n", t);
}



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2) What will be the output of the program?

#include<stdio.h>
void fun(int*, int*);
int main()
{
int i=5, j=2;
fun(&i, &j);
printf("%d, %d", i, j);
return 0;
}
void fun(int *i, int *j)
{
*i = *i**i;
*j = *j**j;
}

3) What will be the output of the program in 16 bit platform (Turbo C under DOS)?

#include<stdio.h>
int main()
{
int fun();
int i;
i = fun();
printf("%d\n", i);
return 0;
}
int fun()
{
_AX = 1990;
}

4) What will be the output of the program?

#include<stdio.h>
int fun(int, int);
typedef int (*pf) (int, int);
int proc(pf, int, int);
int main()
{
printf("%d\n", proc(fun, 6, 6));
return 0;
}
int fun(int a, int b)
{
return (a==b);
}
int proc(pf p, int a, int b)
{
return ((*p)(a, b));
}

5) What will be the output of the program?

#include<stdio.h>
int main()
{
void fun(char*);
char a[100];
a[0] = 'A';
a[1] = 'B';
a[2] = 'C';
a[3] = 'D';
fun(&a[0]);
return 0;
}
void fun(char *a)
{
a++;
printf("%c", *a);
a++;
printf("%c", *a);
}

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