If int is 2 bytes wide.What will be the output of the program?
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If int is 2 bytes wide.What will be the output of the program?

#include <stdio.h>
void fun(char**);
int main()
{
char *argv[] = {"ab", "cd", "ef", "gh"};
fun(argv);
return 0;
}
void fun(char **p)
{
char *t;
t = (p+= sizeof(int))[-1];
printf("%s\n", t);
}



View More Related Question

1) What will be the output of the program?

#include<stdio.h>
int i;
int fun();
int main()
{
while(i)
{
fun();
main();
}
printf("Hello\n");
return 0;
}
int fun()
{
printf("Hi");
}

2) How many times the program will print "Study 2 Online" ?

  #include<stdio.h>
int main()
{
printf("Study 2 Online");
main();
return 0;
}

3) If int is 2 bytes wide.What will be the output of the program?

#include <stdio.h>
void fun(char**);
int main()
{
char *argv[] = {"ab", "cd", "ef", "gh"};
fun(argv);
return 0;
}
void fun(char **p)
{
char *t;
t = (p+= sizeof(int))[-1];
printf("%s\n", t);
}

4) The keyword used to transfer control from a function back to the calling function is

5) What will be the output of the program?

#include<stdio.h>
#include<stdlib.h>
int main()
{
int i=0;
i++;
if(i<=5)
{
printf("Study2Online");
exit(1);
main();
}
return 0;
}

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