If int is 2 bytes wide.What will be the output of the program?

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If int is 2 bytes wide.What will be the output of the program?

#include <stdio.h>
void fun(char**);
int main()
 {
     char *argv[] = {"ab", "cd", "ef", "gh"};
     fun(argv);
     return 0;
 }
void fun(char **p)
 {
     char *t;
     t = (p+= sizeof(int))[-1];
     printf("%s\n", t);
 }

View More Related Question

1) What will be the output of the program?

#include<stdio.h>
#include<stdlib.h>
int main()
 {
     int i=0;
     i++;
     if(i<=5)
     {
         printf("Study2Online");
         exit(1);
         main();
     }
     return 0;
 }

2) What will be the output of the program?

#include<stdio.h>
int main()
 {
     int fun(int);
     int i = fun(10);
     printf("%d\n", --i);
     return 0;
 }
int fun(int i)
 {
    return (i++);
 }

3) How many times the program will print "Study 2 Online" ?

  #include<stdio.h>
  int main()
 {
     printf("Study 2 Online");
     main();
     return 0;
 }

4) What will be the output of the program?

#include<stdio.h>
int fun(int);
int main()
 {
     float k=3;
     fun(k=fun(fun(k)));
     printf("%f\n", k);
     return 0;
 }
int fun(int i)
 {
     i++;
     return i;
 }

5) Which of the following statements are correct about the program?

#include<stdio.h>
int main()
 {
     printf("%p\n", main());
     return 0;
 }