If int is 2 bytes wide.What will be the output of the program?
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If int is 2 bytes wide.What will be the output of the program?

#include <stdio.h>
void fun(char**);
int main()
{
char *argv[] = {"ab", "cd", "ef", "gh"};
fun(argv);
return 0;
}
void fun(char **p)
{
char *t;
t = (p+= sizeof(int))[-1];
printf("%s\n", t);
}



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2) Point out the error in the program

#include<stdio.h>
int main()
{
int a=10;
void f();
a = f();
printf("%d\n", a);
return 0;
}
void f()
{
printf("Hi");
}

3) What will be the output of the program in 16 bit platform (Turbo C under DOS)?

#include<stdio.h>
int main()
{
int fun();
int i;
i = fun();
printf("%d\n", i);
return 0;
}
int fun()
{
_AX = 1990;
}

4) What will be the output of the program?

#include<stdio.h>
void fun(int);
typedef int (*pf) (int, int);
int proc(pf, int, int);
int main()
{
int a=3;
fun(a);
return 0;
}
void fun(int n)
{
if(n > 0)
{
fun(--n);
printf("%d,", n);
fun(--n);
}
}

5) What will be the output of the program?

#include<stdio.h>
int i;
int fun();
int main()
{
while(i)
{
fun();
main();
}
printf("Hello\n");
return 0;
}
int fun()
{
printf("Hi");
}

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